Practice Problems
Fundamental Math
Directions:
On this worksheet you will practice some fundamental math and data analysis skills.
Question 1
The metric prefix mega represents
0.000001 times a quantity
1000 times a quantity
0.001 times a quantity
1000000 times a quantity
Question 2
Red light has an average wavelength of 675 nm. How many mm does this represent?
6.75 x 10
^{-3}
mm
6.75 x 10
^{-5}
mm
6.75 x 10
^{-4}
mm
6.75 x 10
^{-10}
mm
Question 3
0.0078 meters when expressed in scientific notation would be
7.8 x 10
^{3}
meters
7.8 x 10
^{2}
meters
7.8 x 10
^{-2}
meters
7.8 x 10
^{-3}
meters
Question 4
Which statement is TRUE?
1 cm = 10 dm
1 cm = 0.10 m
1 cm = 10000 µm
1 cm = 100 mm
Question 5
Which of the following numbers has exactly 3 significant figures?
10.70
2080
7100
0.0008
Question 6
What is the difference between these two measurements: 28.71 cm and 72.4 cm?
43.7 cm
43.69 cm
43.6 cm
43.8 cm
Question 7
What is the correct reading for the triple beam balance shown below?
243.25 g
243.4 g
240.34 g
243.5 g
Question 8
What is the correct volume reading for the water level in the cylinder shown below?
57.75 mL
55.27 mL
55.5 mL
57.7 mL
Question 9
What is the median of the following data set?
3.31 g
3.21 g
3.38 g
3.54 g
4.16 g
3.31 g
3.62 g
3.50 g
3.31 g
3.54 g
not listed
3.38 g
Question 10
The standard deviation that was calculated for this data set equaled 0.29 grams. Which value in the group shown above falls in an interval beyond 1 standard deviation but less than 2 standard deviations of the mean?
4.16 g
3.54 g
3.38 g
4.16 g
3.21 g
3.62 g
Question 11
Calculate the numerical value of the slope of the following line and then choose the best value from the list below.
15
1.33
0.75
13.3
0.0667
Question 12
If this graph was retitled 'Mass vs Volume', determine the equation for the regression line displayed on this graph and extrapolate the value for the mass which corresponds to a volume of 1.13 cm
^{3}
.
15.8 grams
17 grams
14.5 grams
19.5 grams
PhysicsLAB
Copyright © 1997-2019
Catharine H. Colwell
All rights reserved.
Application Programmer
Mark Acton